(2x+5)(x^2+4x-1)=

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Solution for (2x+5)(x^2+4x-1)= equation:


Simplifying
(2x + 5)(x2 + 4x + -1) = 0

Reorder the terms:
(5 + 2x)(x2 + 4x + -1) = 0

Reorder the terms:
(5 + 2x)(-1 + 4x + x2) = 0

Multiply (5 + 2x) * (-1 + 4x + x2)
(5(-1 + 4x + x2) + 2x * (-1 + 4x + x2)) = 0
((-1 * 5 + 4x * 5 + x2 * 5) + 2x * (-1 + 4x + x2)) = 0
((-5 + 20x + 5x2) + 2x * (-1 + 4x + x2)) = 0
(-5 + 20x + 5x2 + (-1 * 2x + 4x * 2x + x2 * 2x)) = 0
(-5 + 20x + 5x2 + (-2x + 8x2 + 2x3)) = 0

Reorder the terms:
(-5 + 20x + -2x + 5x2 + 8x2 + 2x3) = 0

Combine like terms: 20x + -2x = 18x
(-5 + 18x + 5x2 + 8x2 + 2x3) = 0

Combine like terms: 5x2 + 8x2 = 13x2
(-5 + 18x + 13x2 + 2x3) = 0

Solving
-5 + 18x + 13x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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